faktorisieren 7x^3+56

Lösung

faktorisieren

7 x^{3} + 56

7 (x + 2) (x^{2} - 2 x + 4)

Schritte zur Lösung

7 x^{3} + 56

Klammere gleiche Terme aus

7 : 7 (x^{3} + 8)

= 7 (x^{3} + 8)

Faktorisiere

x^{3} + 8 : (x + 2) (x^{2} - 2 x + 2^{2})

= 7 (x + 2) (x^{2} - 2 x + 2^{2})

2^{2} = 4

= 7 (x + 2) (x^{2} - 2 x + 4)

2 x^{2} < 9 - 6 x

5 x^{2} = 50 0^{2}

3 ∣ x - 5 ∣ + 12 \geq 15

x^{2} + 3 x = - 2

- 126 = 14 k