faktorisieren (4c-d)(c+5d)-9(d-4c)

Lösung

faktorisieren

(4 c - d) (c + 5 d) - 9 (d - 4 c)

(4 c - d) (c + 5 d) - (- 9 (4 c - d))

Schritte zur Lösung

(4 c - d) (c + 5 d) - 9 (d - 4 c)

d - 4 c = - (4 c - d)

= (4 c - d) (c + 5 d) - 9 (- (4 c - d))

Apply rule:

a (- b) = - ab

9 (- (4 c - d)) = - 9 (4 c - d)

= (4 c - d) (c + 5 d) - (- 9 (4 c - d))

s im pl i f y \frac{7 π}{12} \cdot \frac{180}{π}

25 x + 30 = 125 - 5 x

\frac{3 x - 15}{5} = 9

3 x^{2} + 2 x = 0

∣ x + 4 ∣ \leq 6