x^2+3x-28>= 0

Lösung

x^{2} + 3 x - 28 \geq 0

x \leq - 7 or x \geq 4

Intervall-Notation

(- \infty, - 7] \cup [4, \infty)

Schritte zur Lösung

x^{2} + 3 x - 28 \geq 0

Faktorisiere

x^{2} + 3 x - 28 : (x - 4) (x + 7)

(x - 4) (x + 7) \geq 0

Identifiziere die Intervalle

x \leq - 7 or x \geq 4

∣ x + 1 ∣ < 1

5 x^{2} = 26 x + 24

4 (2 - x) > - 2 x - 3 (4 x + 1)

2 ∣ 4 x ∣ = 40

f a c t or x^{3} y^{3} + 216