化简 (5+i)/(1-3i)

解答

化简

\frac{5 + i}{1 - 3 i}

\frac{1}{5} + \frac{8}{5} i

求解步骤

\frac{5 + i}{1 - 3 i}

乘以共轭根式

\frac{1 + 3 i}{1 + 3 i}

= \frac{( 5 + i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )}

化简

\frac{( 5 + i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )} : \frac{2 + 16 i}{10}

= \frac{2 + 16 i}{10}

使用分式法则:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{2}{10} + \frac{16}{10} i

化简

\frac{2}{10} + \frac{16}{10} i : \frac{1}{5} + \frac{8}{5} i

= \frac{1}{5} + \frac{8}{5} i

s im pl i f y \frac{( 2 + 3 i )}{( - 4 - 2 i )}

f a c t or 5 x^{2} - 16 x - 16

∣ x + 4 ∣ = 2

f a c t or 2 x^{3} + x^{2} - 5 x + 2

0.05 (x + 6) + 0.1 (x) = 1.8