s^2-27s=0

解

s^{2} - 27 s = 0

s = 27, s = 0

解答ステップ

s^{2} - 27 s = 0

解くとthe二次式

s_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 27)^{2} - 4 \cdot 1 \cdot 0 = 27

s_{1, 2} = \frac{- ( - 27 ) \pm 27}{2 \cdot 1}

解を分離する

s_{1} = \frac{- ( - 27 ) + 27}{2 \cdot 1}, s_{2} = \frac{- ( - 27 ) - 27}{2 \cdot 1}

s = \frac{- ( - 27 ) + 27}{2 \cdot 1} : 27

s = \frac{- ( - 27 ) - 27}{2 \cdot 1} : 0

二次equationの解:

s = 27, s = 0