2^k>= 36

Lösung

2^{k} \geq 36

k \geq 2 lo g_{2} (6)

Intervall-Notation

[2 lo g_{2} (6), \infty)

Dezimale

k \geq 5.16992 \dots

Schritte zur Lösung

2^{k} \geq 36

Wende Exponentenregel an

k \geq 2 lo g_{2} (6)

f a c t or n^{2} + 16 n + 63

- 140 < 10 x

x^{2} = 16 x

4 n^{2} + 5 n - 5 = 0

\frac{1}{4} h^{2} - \frac{3}{4} h = 0