faktorisieren 5(a+b)^3-2(a+b)+(a+b)^3

Lösung

faktorisieren

5 (a + b)^{3} - 2 (a + b) + (a + b)^{3}

2 (a + b) (3 a^{2} + 6 ab + 3 b^{2} - 1)

Schritte zur Lösung

5 (a + b)^{3} - 2 (a + b) + (a + b)^{3}

Addiere gleiche Elemente:

5 (a + b)^{3} + (a + b)^{3} = 6 (a + b)^{3}

= 6 (a + b)^{3} - 2 (a + b)

Klammere gleiche Terme aus

2 (a + b) : 2 (a + b) (3 (a + b)^{2} - 1)

= 2 (a + b) (3 (a + b)^{2} - 1)

Schreibe

3 (a + b)^{2} - 1

um:

3 a^{2} + 6 ab + 3 b^{2} - 1

= 2 (a + b) (3 a^{2} + 6 ab + 3 b^{2} - 1)

s im pl i f y \frac{k ( 2 k - 1 ) ( 2 k + 1 )}{3} + (2 (k + 1) - 1)^{2}

s im pl i f y \frac{9}{2} - 1

s im pl i f y \frac{3}{b ^{2} - 4 b - 5} - \frac{2}{b ^{2} - 6 b + 5}

f a c t or 72 x + 15 x^{2} - 3 x^{3}

x^{2} - 3 x - 2 = 0