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Beliebt Algebra >

faktorisieren (3x^2-6x+9)^3

Lösung

faktorisieren

(3 x^{2} - 6 x + 9)^{3}

Lösung

27 (x^{2} - 2 x + 3)^{3}

Schritte zur Lösung

(3 x^{2} - 6 x + 9)^{3}

Faktorisiere

3 x^{2} - 6 x + 9 : 3 (x^{2} - 2 x + 3)

= (3 (x^{2} - 2 x + 3))^{3}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(3 (x^{2} - 2 x + 3))^{3} = 3^{3} (x^{2} - 2 x + 3)^{3}

= 3^{3} (x^{2} - 2 x + 3)^{3}

3^{3} = 27

= 27 (x^{2} - 2 x + 3)^{3}

Beliebte Beispiele

1 - 5 x + 3 x^{2} = x^{2}

4/5 x-1/4 <= 7/10 x-4/5

\frac{4}{5} x - \frac{1}{4} \leq \frac{7}{10} x - \frac{4}{5}

5 x^{2} - 4 x - 1 = 0

∣ 1 + 3 x ∣ - 3 \geq 2

(5x-4)+(9x-68)>= x-1

(5 x - 4) + (9 x - 68) \geq x - 1