展开 F(0,-2)

解答

展开

F (0, - 2)

0 \cdot F, - 2 F

求解步骤

F (0, - 2)

= (0, - 2) F

使用分配律:

a (b - c) = ab - a c

a = F, b = 0,, c = 2

= F \cdot 0, - F \cdot 2

= 0 \cdot F, - 2 F

e x p an d (sin (x) + cos (2 x))^{2}

e x p an d 4 (\frac{3}{4} x + y = - 3)

e x p an d \frac{34 - 17 s}{( 2 s - 1 ) ( s ^{2} - 2 s + 5 )}

e x p an d \frac{4 π ( h ^{2} + 8 h + 8 ) ^{2}}{3 h ^{2}}

e x p an d lo g_{8} (x y)