展开 ((4x+1)(3x-1))/(6x^2)

解答

展开

\frac{( 4 x + 1 ) ( 3 x - 1 )}{6 x ^{2}}

2 - \frac{1}{6 x} - \frac{1}{6 x ^{2}}

求解步骤

\frac{( 4 x + 1 ) ( 3 x - 1 )}{6 x ^{2}}

乘开

(4 x + 1) (3 x - 1) : 12 x^{2} - x - 1

= \frac{12 x ^{2} - x - 1}{6 x ^{2}}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 x ^{2} - x - 1}{6 x ^{2}} = \frac{12 x ^{2}}{6 x ^{2}} - \frac{x}{6 x ^{2}} - \frac{1}{6 x ^{2}}

= \frac{12 x ^{2}}{6 x ^{2}} - \frac{x}{6 x ^{2}} - \frac{1}{6 x ^{2}}

消掉

\frac{12 x ^{2}}{6 x ^{2}} : 2

= 2 - \frac{x}{6 x ^{2}} - \frac{1}{6 x ^{2}}

消掉

\frac{x}{6 x ^{2}} : \frac{1}{6 x}

= 2 - \frac{1}{6 x} - \frac{1}{6 x ^{2}}

e x p an d lo g_{10} (3) (x - 6)

e x p an d (L^{3} \cdot cos (q) - sin (q))^{2}

e x p an d \frac{1}{s ( s - 1 ) ^{2}}

s im pl i f y (1 - sec (x)) (sec^{2} (x))

s im pl i f y 2 (x + i y)^{2}