展开 3x(3x-40+1=0)

解答

展开

3 x (3 x - 40 + 1 = 0)

9 x^{2} - 117 x = 0

求解步骤

3 x (3 x - 40 + 1 = 0)

= 3 x (3 x - 40 + 1 \cdot 0 =)

打开括号

3 x \cdot 3 x + 3 x (- 40) + 3 x \cdot 1 = 0

使用加减运算法则

+ (- a) = - a

3 \cdot 3 xx - 3 \cdot 40 x + 3 \cdot 1 \cdot x = 0

乘开

3 \cdot 3 xx - 3 \cdot 40 x + 3 \cdot 1 \cdot x : 9 x^{2} - 117 x

9 x^{2} - 117 x = 0

e x p an d \frac{7 x + 10}{( x + 1 ) ( x ^{2} - 4 )}

e x p an d ((3 x^{3} + 5 y)^{2})^{2}

e x p an d lo g_{10} \frac{( x + 4 ) ^{5}}{x ^{3}}

e x p an d \frac{p ( x )}{( x ^{2} + 1 ) ( x - 3 )}

e x p an d (k + 1)!