展开 ((2x+1)^3)/3

解答

展开

\frac{( 2 x + 1 ) ^{3}}{3}

\frac{8 x ^{3}}{3} + 4 x^{2} + 2 x + \frac{1}{3}

求解步骤

\frac{( 2 x + 1 ) ^{3}}{3}

(2 x + 1)^{3} = 8 x^{3} + 12 x^{2} + 6 x + 1

= \frac{8 x ^{3} + 12 x ^{2} + 6 x + 1}{3}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 x ^{3} + 12 x ^{2} + 6 x + 1}{3} = \frac{8 x ^{3}}{3} + \frac{12 x ^{2}}{3} + \frac{6 x}{3} + \frac{1}{3}

= \frac{8 x ^{3}}{3} + \frac{12 x ^{2}}{3} + \frac{6 x}{3} + \frac{1}{3}

数字相除:

\frac{12}{3} = 4

= \frac{8 x ^{3}}{3} + 4 x^{2} + \frac{6 x}{3} + \frac{1}{3}

数字相除:

\frac{6}{3} = 2

= \frac{8 x ^{3}}{3} + 4 x^{2} + 2 x + \frac{1}{3}

s im pl i f y \frac{5 ( 2 3 + 3 )}{3}

e x p an d A (4, - 5) B (0, - 3)

e x p an d \frac{260 π ( 4 2 - 8 )}{3}

e x p an d (x = 2 x + x^{2} + \frac{1}{3} x^{3}) d x

e x p an d (a + b 2) (c + d 2) (e + f 2)