展开 ((2+2x)/(1+y^2))^2

解答

展开

(\frac{2 + 2 x}{1 + y ^{2}})^{2}

\frac{4 + 8 x + 4 x ^{2}}{1 + 2 y ^{2} + y ^{4}}

求解步骤

(\frac{2 + 2 x}{1 + y ^{2}})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 + 2 x ) ^{2}}{( 1 + y ^{2} ) ^{2}}

(1 + y^{2})^{2} = 1 + 2 y^{2} + y^{4}

= \frac{( 2 + 2 x ) ^{2}}{1 + 2 y ^{2} + y ^{4}}

(2 + 2 x)^{2} = 4 + 8 x + 4 x^{2}

= \frac{4 + 8 x + 4 x ^{2}}{1 + 2 y ^{2} + y ^{4}}

e x p an d (1, - 2) y (- 4, 1)

e x p an d \frac{( x ^{2} - 49 ) ( x + 9 )}{x ^{2} + 2 x - 24}

e x p an d (7 - 5 \frac{x}{1977326743})^{18}

e x p an d (- t) (e^{- t} - e^{2 t})

e x p an d 1 (0 - 3) (- x - 3 = y)