展开-(6x+6)sin(3x^2+3x)

解答

展开

- (6 x + 6) sin (3 x^{2} + 3 x)

- 6 x sin (3 x^{2} + 3 x) - 6 sin (3 x^{2} + 3 x)

求解步骤

- (6 x + 6) sin (3 x^{2} + 3 x)

= - sin (3 x^{2} + 3 x) (6 x + 6)

使用分配律:

a (b + c) = ab + a c

- sin (3 x^{2} + 3 x) (6 x + 6) = - sin (3 x^{2} + 3 x) \cdot 6 x - sin (3 x^{2} + 3 x) \cdot 6

= - sin (3 x^{2} + 3 x) \cdot 6 x - sin (3 x^{2} + 3 x) \cdot 6

= - 6 x sin (3 x^{2} + 3 x) - 6 sin (3 x^{2} + 3 x)

e x p an d \frac{( x ^{2} + x ^{2} )}{( 2 - x ^{2} )}

e x p an d l im x \Rightarrow 0 (1 + x) - 2 - 1 x

e x p an d \frac{x ^{2} y ^{''} ( x ) + x y ^{'} ( x ) - y ( x + 1 ) + 1}{( x + 1 ) x ^{2}}

e x p an d x^{3} - 6 x^{3} + 8 x

e x p an d 2 x - ln ∣ 2 (x - y) + 1 ∣ + 2 y