erweitern 3-sin(2x^2-3x-1)(4x-3)

Lösung

erweitern

3 - sin (2 x^{2} - 3 x - 1) (4 x - 3)

3 - 4 x sin (2 x^{2} - 3 x - 1) + 3 sin (2 x^{2} - 3 x - 1)

Schritte zur Lösung

3 - sin (2 x^{2} - 3 x - 1) (4 x - 3)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

- sin (2 x^{2} - 3 x - 1) (4 x - 3) = - sin (2 x^{2} - 3 x - 1) \cdot 4 x - (- sin (2 x^{2} - 3 x - 1)) \cdot 3

= 3 - sin (2 x^{2} - 3 x - 1) \cdot 4 x - (- sin (2 x^{2} - 3 x - 1)) \cdot 3

Vereinfache

- sin (2 x^{2} - 3 x - 1) \cdot 4 x - (- sin (2 x^{2} - 3 x - 1)) \cdot 3 : - 4 x sin (2 x^{2} - 3 x - 1) + 3 sin (2 x^{2} - 3 x - 1)

= 3 - 4 x sin (2 x^{2} - 3 x - 1) + 3 sin (2 x^{2} - 3 x - 1)

e x p an d (3 x^{2} + 3 y^{2} \frac{d y}{d x}) (x^{2} + y^{2})

e x p an d \frac{2 ( 2 n + 3 ) \cdot ( 5 n + 3 )}{3 ( 5 n + 8 ) \cdot ( 2 n + 1 )}

e x p an d f (x) (sin (\frac{x}{2}) = 2 + cos (x))

e x p an d x + 8 x + 16

e x p an d (cos (x) + a sin (x))^{2}