erweitern e^{2/x-c}*(-1/2 e^{(2+cx)/x}+c)

Lösung

erweitern

e^{\frac{2}{x} - c} \cdot (- \frac{1}{2} e^{\frac{2 + c x}{x}} + c)

- \frac{e ^{\frac{4}{x}}}{2} + c e^{\frac{2}{x} - c}

Schritte zur Lösung

e^{\frac{2}{x} - c} (- \frac{1}{2} e^{\frac{2 + c x}{x}} + c)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = e^{\frac{2}{x} - c}, b = - \frac{1}{2} e^{\frac{2 + c x}{x}}, c = c

= e^{\frac{2}{x} - c} (- \frac{1}{2} e^{\frac{2 + c x}{x}}) + e^{\frac{2}{x} - c} c

Wende Minus-Plus Regeln an

+ (- a) = - a

= - \frac{1}{2} e^{\frac{2 + c x}{x}} e^{\frac{2}{x} - c} + c e^{\frac{2}{x} - c}

\frac{1}{2} e^{\frac{2 + c x}{x}} e^{\frac{2}{x} - c} = \frac{e ^{\frac{4}{x}}}{2}

= - \frac{e ^{\frac{4}{x}}}{2} + c e^{\frac{2}{x} - c}

e x p an d \frac{16 a ^{2} + 15 b}{20 ab}

e x p an d 2^{6} (x^{- 2})^{6}

e x p an d 4 x z + x x^{2} + 4 (7.5 - 3 z)^{2}

e x p an d A (s (s^{2} + 16))

e x p an d \frac{4}{s ( s + 3 )}