faktorisieren 9x^{4/7}-1

Lösung

faktorisieren

9 x^{\frac{4}{7}} - 1

(3 x^{\frac{2}{7}} + 1) (3 x^{\frac{2}{7}} - 1)

Schritte zur Lösung

9 x^{\frac{4}{7}} - 1

Schreibe

x^{\frac{4}{7}}

um:

(7 x)^{4}

= 9 (7 x)^{4} - 1

Schreibe

9 (7 x)^{4} - 1

um:

(3 (7 x)^{2})^{2} - 1^{2}

= (3 (7 x)^{2})^{2} - 1^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(3 (7 x)^{2})^{2} - 1^{2} = (3 (7 x)^{2} + 1) (3 (7 x)^{2} - 1)

= (3 (7 x)^{2} + 1) (3 (7 x)^{2} - 1)

(7 x)^{2} = x^{\frac{2}{7}}

= (3 x^{\frac{2}{7}} + 1) (3 (7 x)^{2} - 1)

(7 x)^{2} = x^{\frac{2}{7}}

= (3 x^{\frac{2}{7}} + 1) (3 x^{\frac{2}{7}} - 1)

f a c t or 2 x^{3} + 3 x^{2} - 14 x - 21

f a c t or x^{2} - 5 x + \frac{25}{4}

- \frac{3}{4} = \frac{x}{24}

- 9 = z + 22

s im pl i f y \frac{( 8 ^{6} ) ( 8 ^{- 3} ) ( 4 ^{- 2} )}{2}