化简 (2-2i^3)/(3-i^5)+(-2i)/(1-i)

解答

化简

\frac{2 - 2 i ^{3}}{3 - i ^{5}} + \frac{- 2 i}{1 - i}

\frac{7}{5} - \frac{1}{5} i

求解步骤

\frac{2 - 2 i ^{3}}{3 - i ^{5}} + \frac{- 2 i}{1 - i}

\frac{2 - 2 i ^{3}}{3 - i ^{5}} = \frac{2 ( 1 + 2 i )}{5}

\frac{- 2 i}{1 - i} = - i + 1

= \frac{2 ( 1 + 2 i )}{5} - i + 1

合并

\frac{2 ( 1 + 2 i )}{5} - i + 1 : \frac{- i + 7}{5}

= \frac{- i + 7}{5}

Rewrite in standard complex form:

\frac{7}{5} - \frac{1}{5} i

= \frac{7}{5} - \frac{1}{5} i

(2 x + 2)^{2} + (4 x)^{2} < (5 x + 1)^{2}

6 (n + 3) + 2 > 3 (n + 2) + 6

0.4 r - 0.13 - 0.7 r = 3 r - 5.74

5 (x^{2} - 2) - 5 = 5

3 v > 6