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受欢迎的代数 >

(2x^2)/5+(5x)/4 =10

解答

\frac{2 x ^{2}}{5} + \frac{5 x}{4} = 10

解答

x = \frac{- 25 + 5 281}{16}, x = \frac{- 25 - 5 281}{16}

+1

十进制

x = 3.67595 \dots, x = - 6.80095 \dots

求解步骤

\frac{2 x ^{2}}{5} + \frac{5 x}{4} = 10

找到

5, 4

的最小公倍数:

20

乘以最小公倍数=

20

\frac{2 x ^{2}}{5} \cdot 20 + \frac{5 x}{4} \cdot 20 = 10 \cdot 20

化简

8 x^{2} + 25 x = 200

将

200

para o lado esquerdo

8 x^{2} + 25 x - 200 = 0

使用求根公式求解

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 8 ( - 200 )}{2 \cdot 8}

2 5^{2} - 4 \cdot 8 (- 200) = 5281

x_{1, 2} = \frac{- 25 \pm 5 281}{2 \cdot 8}

将解分隔开

x_{1} = \frac{- 25 + 5 281}{2 \cdot 8}, x_{2} = \frac{- 25 - 5 281}{2 \cdot 8}

x = \frac{- 25 + 5 281}{2 \cdot 8} : \frac{- 25 + 5 281}{16}

x = \frac{- 25 - 5 281}{2 \cdot 8} : \frac{- 25 - 5 281}{16}

二次方程组的解是:

x = \frac{- 25 + 5 281}{16}, x = \frac{- 25 - 5 281}{16}

作图

流行的例子

solvefor a,c^2=a^2+b^2

so l v e f or a, c^{2} = a^{2} + b^{2}

solvefor x,5x^2-2xy+2y^2-2y-71=0

so l v e f or x, 5 x^{2} - 2 x y + 2 y^{2} - 2 y - 71 = 0

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- 4 x^{2} + 6 x - 2 = 0

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