0=ax^2+bx+c

解

0 = a x^{2} + b x + c

x = \frac{- b + b ^{2} - 4 a c}{2 a}, x = \frac{- b - b ^{2} - 4 a c}{2 a}; a \neq = 0

解答ステップ

0 = a x^{2} + b x + c

辺を交換する

a x^{2} + b x + c = 0

解くとthe二次式

x_{1, 2} = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{- b + b ^{2} - 4 a c}{2 a}; a \neq = 0

x = \frac{- b - b ^{2} - 4 a c}{2 a}; a \neq = 0

二次equationの解:

x = \frac{- b + b ^{2} - 4 a c}{2 a}, x = \frac{- b - b ^{2} - 4 a c}{2 a}; a \neq = 0