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人気のある代数 >

(a+1)x^2+(2a+1)x-a=30

解

(a + 1) x^{2} + (2 a + 1) x - a = 30

解

x = \frac{- 2 a - 1 + 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}, x = \frac{- 2 a - 1 - 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}; a \neq = - 1

解答ステップ

(a + 1) x^{2} + (2 a + 1) x - a = 30

30

を左側に移動します

(a + 1) x^{2} + (2 a + 1) x - a - 30 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( 2 a + 1 ) \pm ( 2 a + 1 ) ^{2} - 4 ( a + 1 ) ( - a - 30 )}{2 ( a + 1 )}

簡素化

(2 a + 1)^{2} - 4 (a + 1) (- a - 30) : 8 a^{2} + 128 a + 121

x_{1, 2} = \frac{- ( 2 a + 1 ) \pm 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}; a \neq = - 1

解を分離する

x_{1} = \frac{- ( 2 a + 1 ) + 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}, x_{2} = \frac{- ( 2 a + 1 ) - 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}

x = \frac{- ( 2 a + 1 ) + 8 a ^{2} + 128 a + 121}{2 ( a + 1 )} : \frac{- 2 a - 1 + 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}

x = \frac{- ( 2 a + 1 ) - 8 a ^{2} + 128 a + 121}{2 ( a + 1 )} : \frac{- 2 a - 1 - 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}

二次equationの解:

x = \frac{- 2 a - 1 + 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}, x = \frac{- 2 a - 1 - 8 a ^{2} + 128 a + 121}{2 ( a + 1 )}; a \neq = - 1

グラフ

人気の例

solvefor x,x^2+x-1=0

so l v e f or x, x^{2} + x - 1 = 0

1.77*10^{-6}-1.77*10^{-5}x-x^2=0

1.77 \cdot 1 0^{- 6} - 1.77 \cdot 1 0^{- 5} x - x^{2} = 0

4 x^{2} - x = 3

x^{2} + x^{2} = 2^{4}

4 x^{2} - 14 x + 12 = 0