c^2-4c=0

解

c^{2} - 4 c = 0

c = 4, c = 0

解答ステップ

c^{2} - 4 c = 0

解くとthe二次式

c_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

c_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

解を分離する

c_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, c_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

c = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

c = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

二次equationの解:

c = 4, c = 0