x^2+2sqrt(3)x-72=0

解答

x^{2} + 23 x - 72 = 0

x = 43, x = - 63

十进制

x = 6.92820 \dots, x = - 10.39230 \dots

求解步骤

x^{2} + 23 x - 72 = 0

使用求根公式求解

x_{1, 2} = \frac{- 2 3 \pm ( 2 3 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(23)^{2} - 4 \cdot 1 \cdot (- 72) = 103

x_{1, 2} = \frac{- 2 3 \pm 10 3}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 2 3 + 10 3}{2 \cdot 1}, x_{2} = \frac{- 2 3 - 10 3}{2 \cdot 1}

x = \frac{- 2 3 + 10 3}{2 \cdot 1} : 43

x = \frac{- 2 3 - 10 3}{2 \cdot 1} : - 63

二次方程组的解是:

x = 43, x = - 63

a^{2} + 4 a - 12 = 0

c = 0.05 x^{2} - 5 x + 500

6^{2} + 7^{2} = x^{2}

co m pl e t es q u a re 2 x^{2} - 12 x + 7

co m pl e t es q u a re 2 s^{2} + s + 2