t^2-9t-10=0

解

t^{2} - 9 t - 10 = 0

t = 10, t = - 1

解答ステップ

t^{2} - 9 t - 10 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 10) = 11

t_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 1}, t_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 1}

t = \frac{- ( - 9 ) + 11}{2 \cdot 1} : 10

t = \frac{- ( - 9 ) - 11}{2 \cdot 1} : - 1

二次equationの解:

t = 10, t = - 1