(x+5)^2(x+3)(x-1)>0

Lösung

(x + 5)^{2} (x + 3) (x - 1) > 0

x < - 5 or - 5 < x < - 3 or x > 1

Intervall-Notation

(- \infty, - 5) \cup (- 5, - 3) \cup (1, \infty)

Schritte zur Lösung

(x + 5)^{2} (x + 3) (x - 1) > 0

Identifiziere die Intervalle

x < - 5 or - 5 < x < - 3 or x > 1

8 b^{2} + 11 b - 11 = 6

3 x^{2} + 7 x - 20 = 0

2 m^{2} + 10 = 0

f a c t or 7 x + 7

\frac{5 x + 1}{3} < 7