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受欢迎的代数 >

solvefor A,(A+B)(A+C)=A+BC

解答

求解

A, (A + B) (A + C) = A + BC

解答

A = 0, A = - C - B + 1

求解步骤

(A + B) (A + C) = A + BC

展开

(A + B) (A + C) : A^{2} + A C + A B + BC

A^{2} + A C + A B + BC = A + BC

将

BC

para o lado esquerdo

A^{2} + A C + A B = A

将

A

para o lado esquerdo

A^{2} + A C + A B - A = 0

改写成标准形式

a x^{2} + b x + c = 0

A^{2} + (C + B - 1) A = 0

使用求根公式求解

A_{1, 2} = \frac{- ( C + B - 1 ) \pm ( C + B - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

化简

(C + B - 1)^{2} - 4 \cdot 1 \cdot 0 : B + C - 1

A_{1, 2} = \frac{- ( C + B - 1 ) \pm ( B + C - 1 )}{2 \cdot 1}

将解分隔开

A_{1} = \frac{- ( C + B - 1 ) + B + C - 1}{2 \cdot 1}, A_{2} = \frac{- ( C + B - 1 ) - ( B + C - 1 )}{2 \cdot 1}

A = \frac{- ( C + B - 1 ) + B + C - 1}{2 \cdot 1} : 0

A = \frac{- ( C + B - 1 ) - ( B + C - 1 )}{2 \cdot 1} : - C - B + 1

二次方程组的解是:

A = 0, A = - C - B + 1

作图

流行的例子

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