solvefor x,x^2+2ax+a^2-n=0

解

x, x^{2} + 2 a x + a^{2} - n = 0

x = - a + n, x = - a - n

解答ステップ

x^{2} + 2 a x + a^{2} - n = 0

解くとthe二次式

x_{1, 2} = \frac{- 2 a \pm ( 2 a ) ^{2} - 4 \cdot 1 \cdot ( a ^{2} - n )}{2 \cdot 1}

簡素化

(2 a)^{2} - 4 \cdot 1 \cdot (a^{2} - n) : 2 n

x_{1, 2} = \frac{- 2 a \pm 2 n}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 2 a + 2 n}{2 \cdot 1}, x_{2} = \frac{- 2 a - 2 n}{2 \cdot 1}

x = \frac{- 2 a + 2 n}{2 \cdot 1} : - a + n

x = \frac{- 2 a - 2 n}{2 \cdot 1} : - a - n

二次equationの解:

x = - a + n, x = - a - n