ln(2x^2-x)<0

Lösung

ln (2 x^{2} - x) < 0

- \frac{1}{2} < x < 0 or \frac{1}{2} < x < 1

Intervall-Notation

(- \frac{1}{2}, 0) \cup (\frac{1}{2}, 1)

Dezimale

- 0.5 < x < 0 or 0.5 < x < 1

Schritte zur Lösung

ln (2 x^{2} - x) < 0

Wende die log Regel an

2 x^{2} - x < 1 and 2 x^{2} - x > 0

2 x^{2} - x < 1 and 2 x^{2} - x > 0 : - \frac{1}{2} < x < 0 or \frac{1}{2} < x < 1

- \frac{1}{2} < x < 0 or \frac{1}{2} < x < 1

f a c t or a^{3} - a

f a c t or 15 n^{2} - n - 28

x^{2} + 9 > 6 x

x^{2} + 12 = 7 x

- 10 b + 7 = 17