Z=(1-(3+i)^2(1-2i))/(2i^{77)-i^{726}}

Lösung

Z = \frac{1 - ( 3 + i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}}

Z = \frac{1}{5} + i \frac{48}{5}

Schritte zur Lösung

Z = \frac{1 - ( 3 + i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}}

Vereinfache

\frac{1 - ( 3 + i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}} : \frac{1}{5} + i \frac{48}{5}

Z = \frac{1}{5} + i \frac{48}{5}

\frac{4}{15} z + \frac{5}{6} z + \frac{1}{2} = 1 \frac{3}{5}

y + 3 = 10

4 = 3 x + 4

so l v e f or x, g = - \frac{1}{2} f

- 9 x + 3 = - 7 x - 15