faktorisieren 2x^5-x^4-10x^3+5x^2+8x-4

Lösung

faktorisieren

2 x^{5} - x^{4} - 10 x^{3} + 5 x^{2} + 8 x - 4

(x - 1) (x + 1) (2 x - 1) (x + 2) (x - 2)

Schritte zur Lösung

2 x^{5} - x^{4} - 10 x^{3} + 5 x^{2} + 8 x - 4

Wende den rationalen Nullstellentest an

= (x - 1) \frac{2 x ^{5} - x ^{4} - 10 x ^{3} + 5 x ^{2} + 8 x - 4}{x - 1}

\frac{2 x ^{5} - x ^{4} - 10 x ^{3} + 5 x ^{2} + 8 x - 4}{x - 1} = 2 x^{4} + x^{3} - 9 x^{2} - 4 x + 4

= (x - 1) (2 x^{4} + x^{3} - 9 x^{2} - 4 x + 4)

Faktorisiere

2 x^{4} + x^{3} - 9 x^{2} - 4 x + 4 : (x + 1) (2 x - 1) (x + 2) (x - 2)

= (x - 1) (x + 1) (2 x - 1) (x + 2) (x - 2)

f a c t or 63 a - 70

s im pl i f y (x^{3} y^{2} z^{3})^{\frac{1}{13}}

s im pl i f y (4 x^{4} y^{- 3})^{\frac{1}{2}}

f a c t or 8 x^{4} + 16 x^{3} - 4 x^{2}

s im pl i f y \frac{( x ^{2} - 4 x + 4 )}{( 2 x - 4 )}