solvefor c,c(t)=5^6*(1+4e^{-2t})^{-1}

解答

求解

c, c (t) = 5^{6} \cdot (1 + 4 e^{- 2 t})^{- 1}

c = \frac{15625}{t ( 1 + 4 e ^{- 2 t} )}; t \neq = 0

求解步骤

c (t) = 5^{6} (1 + 4 e^{- 2 t})^{- 1}

化简

5^{6} (1 + 4 e^{- 2 t})^{- 1} : \frac{15625}{1 + 4 e ^{- 2 t}}

c t = \frac{15625}{1 + 4 e ^{- 2 t}}

两边除以

t; t \neq = 0

c = \frac{15625}{t ( 1 + 4 e ^{- 2 t} )}; t \neq = 0

so l v e f or x, 15 (x - y) - 3 (x - 9) + 5 (x + 6) = 0

so l v e f or x, y = f (x + 1) - 4

so l v e f or x, x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

x \frac{1}{3} + 2 x \frac{2}{3} - x = 0

so l v e f or x, y + 2 = \frac{3}{- 10} \cdot (x - 3)