k=((2f(-2)-4f(f(-3))))/((f(-1)-3))

解答

k = \frac{( 2 f ( - 2 ) - 4 f ( f ( - 3 ) ) )}{( f ( - 1 ) - 3 )}

真

求解步骤

k = \frac{( 2 f ( - 2 ) - 4 f ( f ( - 3 ) ) )}{( f ( - 1 ) - 3 )}

化简

\frac{2 f ( - 2 ) - 4 f ( f ( - 3 ) )}{f ( - 1 ) - 3} : \frac{2 f ( - 2 ) - 4 f ( 3 f )}{f ( - 1 ) - 3}

k = \frac{2 f ( - 2 ) - 4 f ( 3 f )}{f ( - 1 ) - 3}

两侧相等

真

\frac{1}{( lo g _{6} ( 12 ) )} + \frac{1}{( lo g _{2} ( 12 ) )} = x

so l v e f or x, 2 (8 x - 5 y) = 34

so l v e f or x, 141 x + 93 y = 189

\frac{( 4 x )}{2 + 3.6} = 104

so l v e f or a, \frac{a}{b} + \frac{1}{5} = \frac{24}{15}