1/(2(x+5)^2+2)=42.5

Lösung

\frac{1}{2 ( x + 5 ) ^{2} + 2} = 42.5

x = - 5 + i \frac{2 1785}{85}, x = - 5 - i \frac{2 1785}{85}

Schritte zur Lösung

\frac{1}{2 ( x + 5 ) ^{2} + 2} = 42.5

Vereinfache

\frac{1}{2 ( x + 5 ) ^{2} + 2} : \frac{1}{2 x ^{2} + 20 x + 52}

\frac{1}{2 x ^{2} + 20 x + 52} = 42.5

Multipliziere beide Seiten mit

2 x^{2} + 20 x + 52

1 = 42.5 (2 x^{2} + 20 x + 52)

Löse

1 = 42.5 (2 x^{2} + 20 x + 52) : x = - 5 + i \frac{2 1785}{85}, x = - 5 - i \frac{2 1785}{85}

x = - 5 + i \frac{2 1785}{85}, x = - 5 - i \frac{2 1785}{85}

x^{- 3} = 2

so l v e f or x, \frac{y}{x} = 5

x (1 - x) = \frac{1}{( x ^{2} + 1 )}

\frac{( x ^{2} + x )}{x} = 1

\frac{3}{6} = \frac{2}{x}