(2-x)(x+3)>0

解答

(2 - x) (x + 3) > 0

- 3 < x < 2

间隔符号

(- 3, 2)

求解步骤

(2 - x) (x + 3) > 0

确定区间

- 3 < x < 2

so l v e f or x, 2 (2 x - 1) > 4 x - 6 u

\frac{( x + 1 ) ( x - 1 ) ( x + 2 )}{( x ^{2} + 3 x + 2 ) ( x + 5 )} < 0

x (x^{2} - 1) \leq 0

\frac{( ( x + 2 ) ( x ^{2} - 2 x + 1 ) )}{( - 4 + 3 x - 2 x ^{2} )} \geq 0

(x^{3} - 1) (x^{3} + 1) (3 - x) \cdot x \geq 0