(6x)/7 >= 0

解答

\frac{6 x}{7} \geq 0

x \geq 0

间隔符号

[0, \infty)

求解步骤

\frac{6 x}{7} \geq 0

在两边乘以

7

6 x \geq 0

两边除以

6

x \geq 0

f a c t or (8 c - d) (c + 5 d) - 3 (d - 8 c)

5 x^{2} - 31 x + 6 = 0

0.0001 = 2.5263 \cdot 1 0^{- 9} (x - (6 \cdot 1 0^{3}))

3 (2 x + 1) - \frac{x + 1}{2} = \frac{1}{2} [x + 2 - \frac{x + 1}{3}]

∣ 1 - 7 x ∣ + 5 \geq 8