簡約 (6-2x+7x^2)-(10x-3+3x^2)

解

簡約

(6 - 2 x + 7 x^{2}) - (10 x - 3 + 3 x^{2})

4 x^{2} - 12 x + 9

解答ステップ

(6 - 2 x + 7 x^{2}) - (10 x - 3 + 3 x^{2})

規則を適用する:

(a) = a

(6 - 2 x + 7 x^{2}) = 6 - 2 x + 7 x^{2}

= 6 - 2 x + 7 x^{2} - (10 x - 3 + 3 x^{2})

分配法則を適用する:

- (a - b) = - a + b

- (10 x - 3 + 3 x^{2}) = - 10 x + 3 - 3 x^{2}

= 6 - 2 x + 7 x^{2} - 10 x + 3 - 3 x^{2}

条件のようなグループ

= 7 x^{2} - 3 x^{2} - 2 x - 10 x + 6 + 3

類似した元を足す:

7 x^{2} - 3 x^{2} = 4 x^{2}

= 4 x^{2} - 2 x - 10 x + 6 + 3

類似した元を足す:

- 2 x - 10 x = - 12 x

= 4 x^{2} - 12 x + 6 + 3

数を足す:

6 + 3 = 9

= 4 x^{2} - 12 x + 9