因式分解 [sec(χ)+tan(χ)][1-sin(χ)]

解答

因式分解

[sec (χ) + tan (χ)] [1 - sin (χ)]

- (sec (χ) + tan (χ)) (sin (χ) - 1)

求解步骤

(sec (χ) + tan (χ)) (1 - sin (χ))

分解

1 - sin (χ) : - (sin (χ) - 1)

= - (sec (χ) + tan (χ)) (sin (χ) - 1)

f (s) = s^{2} + 4

f a c t or x^{2} + 4 x - y^{2} - 2 y + 4 - 1

f a c t or (I n) 5

f a c t or 3 x - 2 y + 2 y z^{4} - 3 x z^{4}

f a c t or (x + 3) (x + 3)