展开 pi^{e^{-1}}-arccos(-1)

解答

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π^{e^{- 1}} - arccos (- 1)

π^{\frac{1}{e}} - π

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- 1.61792 \dots

求解步骤

π^{e^{- 1}} - arccos (- 1)

使用以下普通恒等式:

arccos (- 1) = π

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π^{e^{- 1}} - π

e^{- 1} = \frac{1}{e}

= π^{\frac{1}{e}} - π

e x p an d (1 - 2) x

e x p an d \frac{8 x + 71}{( x + 9 ) ( x + 8 )}

e x p an d \frac{x ^{2} + x + 1}{( x + 1 ) ^{2}}

e x p an d C (2, - 4)

e x p an d e^{(a + b) t} r (t)