展开 ((y^2-4)^2)/2

解答

展开

\frac{( y ^{2} - 4 ) ^{2}}{2}

\frac{y ^{4}}{2} - 4 y^{2} + 8

求解步骤

\frac{( y ^{2} - 4 ) ^{2}}{2}

(y^{2} - 4)^{2} = y^{4} - 8 y^{2} + 16

= \frac{y ^{4} - 8 y ^{2} + 16}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{y ^{4} - 8 y ^{2} + 16}{2} = \frac{y ^{4}}{2} - \frac{8 y ^{2}}{2} + \frac{16}{2}

= \frac{y ^{4}}{2} - \frac{8 y ^{2}}{2} + \frac{16}{2}

数字相除:

\frac{8}{2} = 4

= \frac{y ^{4}}{2} - 4 y^{2} + \frac{16}{2}

数字相除:

\frac{16}{2} = 8

= \frac{y ^{4}}{2} - 4 y^{2} + 8

e x p an d \frac{s}{( s - 1 ) ( s ^{2} + 2 s + 2 )}

e x p an d \frac{5 ( 2 x + h )}{x ( x + h )}

e x p an d π (x + 5)^{2}

e x p an d (x) d x + (x^{2} y + 4 y) d y

e x p an d \frac{x ^{2} + 2 x - 1}{x ( x - 1 )}