erweitern (((x+2)(x-1)(x-3)))/6

Lösung

erweitern

\frac{( ( x + 2 ) ( x - 1 ) ( x - 3 ) )}{6}

\frac{x ^{3}}{6} - \frac{x ^{2}}{3} - \frac{5 x}{6} + 1

Schritte zur Lösung

\frac{( x + 2 ) ( x - 1 ) ( x - 3 )}{6}

Multipliziere aus

(x + 2) (x - 1) (x - 3) : x^{3} - 2 x^{2} - 5 x + 6

= \frac{x ^{3} - 2 x ^{2} - 5 x + 6}{6}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 2 x ^{2} - 5 x + 6}{6} = \frac{x ^{3}}{6} - \frac{2 x ^{2}}{6} - \frac{5 x}{6} + \frac{6}{6}

= \frac{x ^{3}}{6} - \frac{2 x ^{2}}{6} - \frac{5 x}{6} + \frac{6}{6}

Wende Regel an

\frac{a}{a} = 1

\frac{6}{6} = 1

= \frac{x ^{3}}{6} - \frac{2 x ^{2}}{6} - \frac{5 x}{6} + 1

Streiche

\frac{2 x ^{2}}{6} : \frac{x ^{2}}{3}

= \frac{x ^{3}}{6} - \frac{x ^{2}}{3} - \frac{5 x}{6} + 1

e x p an d im x \Rightarrow 2 (2 x^{2} + 2 x)

e x p an d lo g_{10} (0.1)

e x p an d \frac{y ( 3 - y ) ^{2}}{2}

e x p an d \frac{( 2 + x ) ( 7 - x )}{( 5 - x ) ( 4 + x )}

e x p an d \frac{6 ( x + h )}{( x + h ) + 2}