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受欢迎的代数 >

6x-8x^2-((x-2))/5 = 1/2 x+3/2-((x-1))/4

解答

6 x - 8 x^{2} - \frac{( x - 2 )}{5} = \frac{1}{2} x + \frac{3}{2} - \frac{( x - 1 )}{4}

解答

x = \frac{111}{320} - i \frac{3 551}{320}, x = \frac{111}{320} + i \frac{3 551}{320}

求解步骤

6 x - 8 x^{2} - \frac{( x - 2 )}{5} = \frac{1}{2} x + \frac{3}{2} - \frac{( x - 1 )}{4}

找到

5, 2, 4

的最小公倍数:

20

乘以最小公倍数=

20

6 x \cdot 20 - 8 x^{2} \cdot 20 - \frac{x - 2}{5} \cdot 20 = \frac{1}{2} x \cdot 20 + \frac{3}{2} \cdot 20 - \frac{x - 1}{4} \cdot 20

化简

120 x - 160 x^{2} - 4 (x - 2) = 10 x + 30 - 5 (x - 1)

展开

120 x - 160 x^{2} - 4 (x - 2) : - 160 x^{2} + 116 x + 8

展开

10 x + 30 - 5 (x - 1) : 5 x + 35

- 160 x^{2} + 116 x + 8 = 5 x + 35

将

35

para o lado esquerdo

- 160 x^{2} + 116 x - 27 = 5 x

将

5 x

para o lado esquerdo

- 160 x^{2} + 111 x - 27 = 0

使用求根公式求解

x_{1, 2} = \frac{- 111 \pm 11 1 ^{2} - 4 ( - 160 ) ( - 27 )}{2 ( - 160 )}

化简

11 1^{2} - 4 (- 160) (- 27) : 3551 i

x_{1, 2} = \frac{- 111 \pm 3 551 i}{2 ( - 160 )}

将解分隔开

x_{1} = \frac{- 111 + 3 551 i}{2 ( - 160 )}, x_{2} = \frac{- 111 - 3 551 i}{2 ( - 160 )}

x = \frac{- 111 + 3 551 i}{2 ( - 160 )} : \frac{111}{320} - i \frac{3 551}{320}

x = \frac{- 111 - 3 551 i}{2 ( - 160 )} : \frac{111}{320} + i \frac{3 551}{320}

二次方程组的解是:

x = \frac{111}{320} - i \frac{3 551}{320}, x = \frac{111}{320} + i \frac{3 551}{320}

作图

流行的例子

4 x + 3 = 2 (5 + 2 x)

∣ 4 - 5 x ∣ \leq 19

2 x < 6

(x - 4) (x + 5) = 0

化简 1/2*8*10

s im pl i f y \frac{1}{2} \cdot 8 \cdot 10