erweitern product(2xy+z)^4

Lösung

erweitern

p ro d u c t (2 x y + z)^{4}

16 p cro t x^{4} y^{4} d u + 32 p cro t x^{3} y^{3} z d u + 24 p cro t x^{2} y^{2} z^{2} d u + 8 p cro t x y z^{3} d u + p cro t z^{4} d u

Schritte zur Lösung

p ro d u c t (2 x y + z)^{4}

(2 x y + z)^{4} = 16 x^{4} y^{4} + 32 x^{3} y^{3} z + 24 x^{2} y^{2} z^{2} + 8 x y z^{3} + z^{4}

= p cro t d u (16 x^{4} y^{4} + 32 x^{3} y^{3} z + 24 x^{2} y^{2} z^{2} + 8 x y z^{3} + z^{4})

= p cro t d u (16 x^{4} y^{4} + 32 x^{3} y^{3} z + 24 x^{2} y^{2} z^{2} + 8 x y z^{3} + z^{4})

Setze Klammern

= p ro d u c t \cdot 16 x^{4} y^{4} + p ro d u c t \cdot 32 x^{3} y^{3} z + p ro d u c t \cdot 24 x^{2} y^{2} z^{2} + p ro d u c t \cdot 8 x y z^{3} + p ro d u c t z^{4}

= 16 p cro t x^{4} y^{4} d u + 32 p cro t x^{3} y^{3} z d u + 24 p cro t x^{2} y^{2} z^{2} d u + 8 p cro t x y z^{3} d u + p cro t z^{4} d u

e x p an d \frac{( - 2 x + 8 ) \cdot x ^{2}}{5}

e x p an d \frac{2 ab + a ( 1 + ab ) + 1}{1 + ( a + 1 ) b}

e x p an d \frac{( 2 b + 3 a ) ( - 6 b + 3 a )}{b ^{2}}

e x p an d \frac{4}{5 ( x + 1 )}

e x p an d \frac{1}{( s + b ) ( s + a )}