|k+7|=3

Lösung

∣ k + 7 ∣ = 3

k = - 10 or k = - 4

Schritte zur Lösung

∣ k + 7 ∣ = 3

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

k + 7 = - 3 or k + 7 = 3

k + 7 = - 3 or k + 7 = 3

k = - 10 or k = - 4

3 - 2 x < x^{2}

s im pl i f y - (x + h)^{2}

6 = 1 + 20 t - 5 t^{2}

5^{2} + 1 2^{2} = c^{2}

2 ∣ x - 2 ∣ > 8