簡約 sqrt(3^2+(75.2-2659))^2

解

簡約

3^{2} + (75.2 - 2659)^{2}

- \frac{12874}{5}

十進法表記

- 2574.8

解答ステップ

(3^{2} + (75.2 - 2659))^{2}

規則を適用する:

a + (b + c) = a + b + c

3^{2} + (75.2 - 2659) = 3^{2} + 75.2 - 2659

= (3^{2} + 75.2 - 2659)^{2}

3^{2} + 75.2 - 2659 = \frac{12874}{5} i

= (\frac{12874}{5} i)^{2}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

(\frac{12874}{5} i)^{2} = (\frac{12874}{5})^{2} i^{2}

= (\frac{12874}{5})^{2} i^{2}

(\frac{12874}{5})^{2} = \frac{12874}{5}

= \frac{12874}{5} i^{2}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{12874 i ^{2}}{5}

簡素化

12874 i^{2} : - 12874

= \frac{- 12874}{5}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{12874}{5}