faktorisieren 216x^3-27

Lösung

faktorisieren

216 x^{3} - 27

27 (2 x - 1) (4 x^{2} + 2 x + 1)

Schritte zur Lösung

216 x^{3} - 27

Klammere gleiche Terme aus

27 : 27 (8 x^{3} - 1)

= 27 (8 x^{3} - 1)

Faktorisiere

8 x^{3} - 1 : (2 x - 1) (2^{2} x^{2} + 2 x + 1)

= 27 (2 x - 1) (2^{2} x^{2} + 2 x + 1)

2^{2} = 4

= 27 (2 x - 1) (4 x^{2} + 2 x + 1)

\frac{( x - 7 )}{( 4 x - 15 )} > 8

- 16 = \frac{8 x}{5}

3 n^{2} + 8 n + 16 = 2 n^{2}

2 \geq \frac{n}{4} - 2

4 x + 3 < 15