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受欢迎的代数 >

j(x)=-x^2+3x+10,j(3x-2)

解答

j (x) = - x^{2} + 3 x + 10, j (3 x - 2)

解答

x = - \frac{- 3 + j + j ^{2} - 6 j + 49}{2}, x = - \frac{- 3 + j - j ^{2} - 6 j + 49}{2}

求解步骤

j (x) = - x^{2} + 3 x + 10

整理后得

j x = - x^{2} + 3 x + 10

交换两边

- x^{2} + 3 x + 10 = j x

将

j x

para o lado esquerdo

- x^{2} + 3 x + 10 - j x = 0

改写成标准形式

a x^{2} + b x + c = 0

- x^{2} + (3 - j) x + 10 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 3 - j ) \pm ( 3 - j ) ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

化简

(3 - j)^{2} - 4 (- 1) \cdot 10 : j^{2} - 6 j + 49

x_{1, 2} = \frac{- ( 3 - j ) \pm j ^{2} - 6 j + 49}{2 ( - 1 )}

将解分隔开

x_{1} = \frac{- ( 3 - j ) + j ^{2} - 6 j + 49}{2 ( - 1 )}, x_{2} = \frac{- ( 3 - j ) - j ^{2} - 6 j + 49}{2 ( - 1 )}

x = \frac{- ( 3 - j ) + j ^{2} - 6 j + 49}{2 ( - 1 )} : - \frac{- 3 + j + j ^{2} - 6 j + 49}{2}

x = \frac{- ( 3 - j ) - j ^{2} - 6 j + 49}{2 ( - 1 )} : - \frac{- 3 + j - j ^{2} - 6 j + 49}{2}

二次方程组的解是:

x = - \frac{- 3 + j + j ^{2} - 6 j + 49}{2}, x = - \frac{- 3 + j - j ^{2} - 6 j + 49}{2}

作图

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