u^2-15u-34=0

解

u^{2} - 15 u - 34 = 0

u = 17, u = - 2

解答ステップ

u^{2} - 15 u - 34 = 0

解くとthe二次式

u_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot ( - 34 )}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot (- 34) = 19

u_{1, 2} = \frac{- ( - 15 ) \pm 19}{2 \cdot 1}

解を分離する

u_{1} = \frac{- ( - 15 ) + 19}{2 \cdot 1}, u_{2} = \frac{- ( - 15 ) - 19}{2 \cdot 1}

u = \frac{- ( - 15 ) + 19}{2 \cdot 1} : 17

u = \frac{- ( - 15 ) - 19}{2 \cdot 1} : - 2

二次equationの解:

u = 17, u = - 2