-q^2+3q-2=0

解

- q^{2} + 3 q - 2 = 0

q = 1, q = 2

解答ステップ

- q^{2} + 3 q - 2 = 0

解くとthe二次式

q_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

3^{2} - 4 (- 1) (- 2) = 1

q_{1, 2} = \frac{- 3 \pm 1}{2 ( - 1 )}

解を分離する

q_{1} = \frac{- 3 + 1}{2 ( - 1 )}, q_{2} = \frac{- 3 - 1}{2 ( - 1 )}

q = \frac{- 3 + 1}{2 ( - 1 )} : 1

q = \frac{- 3 - 1}{2 ( - 1 )} : 2

二次equationの解:

q = 1, q = 2