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受欢迎的代数 >

solvefor x,f(x-2)=x^2+4x+7

解答

求解

x, f (x - 2) = x^{2} + 4 x + 7

解答

x = \frac{- 4 + f + f ^{2} - 16 f - 12}{2}, x = \frac{- 4 + f - f ^{2} - 16 f - 12}{2}

求解步骤

f (x - 2) = x^{2} + 4 x + 7

展开

f (x - 2) : x f - 2 f

x f - 2 f = x^{2} + 4 x + 7

交换两边

x^{2} + 4 x + 7 = x f - 2 f

将

2 f

para o lado esquerdo

x^{2} + 4 x + 7 + 2 f = x f

将

x f

para o lado esquerdo

x^{2} + 4 x + 7 + 2 f - x f = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} + (4 - f) x + 7 + 2 f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 4 - f ) \pm ( 4 - f ) ^{2} - 4 \cdot 1 \cdot ( 7 + 2 f )}{2 \cdot 1}

化简

(4 - f)^{2} - 4 \cdot 1 \cdot (7 + 2 f) : f^{2} - 16 f - 12

x_{1, 2} = \frac{- ( 4 - f ) \pm f ^{2} - 16 f - 12}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( 4 - f ) + f ^{2} - 16 f - 12}{2 \cdot 1}, x_{2} = \frac{- ( 4 - f ) - f ^{2} - 16 f - 12}{2 \cdot 1}

x = \frac{- ( 4 - f ) + f ^{2} - 16 f - 12}{2 \cdot 1} : \frac{- 4 + f + f ^{2} - 16 f - 12}{2}

x = \frac{- ( 4 - f ) - f ^{2} - 16 f - 12}{2 \cdot 1} : \frac{- 4 + f - f ^{2} - 16 f - 12}{2}

二次方程组的解是:

x = \frac{- 4 + f + f ^{2} - 16 f - 12}{2}, x = \frac{- 4 + f - f ^{2} - 16 f - 12}{2}

作图

流行的例子

2 x^{2} - 3 x + 1 = 38

solvefor y,x^2+y^2=Ce^{2x}

so l v e f or y, x^{2} + y^{2} = C e^{2 x}

t^{2} - 5 = 3

0.15 x^{2} = 0.6

completesquare x^2+8x=0

co m pl e t es q u a re x^{2} + 8 x = 0