5R^2-10R=0

解

5 R^{2} - 10 R = 0

R = 2, R = 0

解答ステップ

5 R^{2} - 10 R = 0

解くとthe二次式

R_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 \cdot 0 = 10

R_{1, 2} = \frac{- ( - 10 ) \pm 10}{2 \cdot 5}

解を分離する

R_{1} = \frac{- ( - 10 ) + 10}{2 \cdot 5}, R_{2} = \frac{- ( - 10 ) - 10}{2 \cdot 5}

R = \frac{- ( - 10 ) + 10}{2 \cdot 5} : 2

R = \frac{- ( - 10 ) - 10}{2 \cdot 5} : 0

二次equationの解:

R = 2, R = 0